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Chi-Square Test of Independence Calculator

Test whether two categorical variables are independent, using a 2x2 contingency table.

Result

Chi-Square Statistic (Yates-corrected)
7.9192
Degrees of Freedom
1

The critical value for a 2x2 table at the common 95% confidence level (α = 0.05, df = 1) is 3.841 - a statistic above that suggests the two variables are not independent. Yates' continuity correction is applied, standard practice for 2x2 tables.

About the Chi-Square Independence Test

The Chi-Square Test of Independence Calculator checks whether two categorical variables recorded in a 2x2 table are associated with each other, or whether they behave independently. It's the calculation behind questions like whether a treatment and an outcome are related, or whether two groups differ in how they respond to a categorical question. Unlike the goodness of fit version, this test compares joint counts across two variables rather than a single variable against a hypothesized distribution.

How It Works

Enter the four cell counts of your 2x2 table, split into two rows and two columns. The calculator computes the row totals, column totals, and grand total, then derives the expected count for each cell as the product of its row and column totals divided by the grand total. It then applies Yates' continuity correction, subtracting 0.5 from each absolute deviation before squaring, and sums the four corrected terms to produce the chi-square statistic, always reported with 1 degree of freedom for a 2x2 table.

Chi-square = sum over the four cells of (|Observed - Expected| - 0.5)^2 / Expected, where Expected = (row total x column total) / grand total; degrees of freedom = 1.

Formula & Methodology

By hand, first total each row, each column, and the whole table. For each of the four cells, multiply its row total by its column total and divide by the grand total to get its expected count. Take the absolute difference between each cell's observed and expected count, subtract 0.5, square that, divide by the expected count, and add the four results together.

Examples

A treatment-outcome table

With cell counts of 30, 20, 15, and 35 across the two rows and columns, row and column totals of 50 and 45/55 give expected counts of 22.5, 27.5, 22.5, and 27.5. Working through the Yates-corrected formula produces a chi-square statistic of about 7.92, which exceeds the 3.841 critical value at the 95% confidence level for 1 degree of freedom.

A clinical recovery comparison

In a table where 40 of 50 treated patients recovered versus 25 of 50 untreated patients, the expected counts under independence are 32.5, 17.5, 32.5, and 17.5, and the Yates-corrected chi-square statistic comes out to about 8.62 - again well above 3.841, pointing to a likely association between treatment and recovery.

Advantages

  • Applies Yates' continuity correction automatically, a step that's easy to forget when calculating by hand.
  • Computes row, column, and grand totals internally, so you only need to enter the four raw cell counts.
  • Gives an immediate reference point by reporting the fixed 1 degree of freedom that always applies to a 2x2 table.

Common Mistakes

  • Entering percentages instead of raw counts, which breaks the expected-value calculation since it depends on actual totals.
  • Comparing the result directly to a chi-square table generated without Yates' correction, since the corrected statistic is deliberately smaller.
  • Using this test on data from the same subjects measured twice (paired data), where McNemar's test is the appropriate tool instead.

Edge Cases to Watch For

  • Every row total and column total must be greater than zero; a table with an empty row or column returns an error since the expected counts would be undefined.
  • Yates' continuity correction, the -0.5 adjustment, is applied automatically and is standard for 2x2 tables, but it makes this statistic not directly comparable to the uncorrected chi-square from the goodness of fit calculator.
  • When expected cell counts are small, even the Yates-corrected chi-square approximation can be unreliable; Fisher's Exact Test is the more appropriate tool in that case.

Common Use Cases

  • Clinical researchers testing whether a treatment and a health outcome are associated in a two-group study.
  • UX researchers checking whether a categorical response, like a like or dislike rating, differs between two user segments.
  • Analysts checking whether membership in one category, such as pass or fail, is related to membership in another, such as day or night shift.
Written & fact-checked by the Calculateus TeamLast updated August 5, 2026How we verify our formulas

Frequently asked questions

What does this test check versus the Chi-Square Goodness of Fit Calculator?

Goodness of fit compares a single categorical variable's observed frequencies to a hypothesized distribution. This test instead checks whether two categorical variables are associated with each other, using a contingency table of joint counts - for example, whether treatment group and outcome are related.

Conclusion

This calculator packages the row and column arithmetic and Yates' correction into a single 2x2 chi-square statistic with its degrees of freedom. Compare the result to the standard 3.841 critical value at the 95% confidence level, or to a full critical value table for other significance levels, to judge whether the two variables appear related.