Calculateus

Combination Calculator (nCr)

Calculate the number of combinations (unordered selections) of r items from a set of n.

Result

C(10, 3)
120
StepOperationRunning Total
1× 10 ÷ 110
2× 9 ÷ 245
3× 8 ÷ 3120

About the Combination Calculator

When you're selecting a group where order doesn't matter - like picking 3 team members from 10 candidates - combinations, not permutations, give the right count. Our Combination Calculator finds nCr, the number of unordered selections.

How It Works

The calculator divides the permutation count by r factorial (the number of ways to reorder the same selected group), since combinations treat every reordering of the same group as identical.

C(n, r) = n! ÷ (r! × (n − r)!)

Formula & Methodology

Combinations start from the permutation count and then remove the overcounting caused by treating different orderings of the same group as distinct - since any group of r items can be arranged in r! different orders, dividing the permutation count P(n,r) by r! collapses all those equivalent orderings down to a single count per unique group. That's exactly why C(n,r) = P(n,r) ÷ r! = n! ÷ (r! × (n−r)!).

Step-by-Step: Calculating It By Hand

  1. 1Confirm r does not exceed n.
  2. 2Calculate n factorial, r factorial, and (n−r) factorial.
  3. 3Multiply r! by (n−r)!.
  4. 4Divide n! by that product to find the number of unordered selections.

Examples

Choosing a team

Selecting an unordered group of 3 people from 10 candidates gives C(10,3) = 120 possible combinations - much smaller than the 720 permutations of the same numbers, since order doesn't matter here.

Lottery-style selection

Choosing 6 numbers from 49 (a common lottery format) gives C(49,6) = 13,983,816 - illustrating just how large combination counts can get even from a modest range.

Advantages

  • Correctly calculates unordered selections, distinct from permutations
  • Handles large n and r values efficiently
  • Useful for probability calculations involving groups or subsets
  • Standard tool across statistics, probability, and combinatorics

Common Mistakes

  • Using combinations when order actually matters (or vice versa)
  • Forgetting combinations are always smaller than or equal to the corresponding permutation count
  • Miscounting n or r, especially in multi-step probability problems combining several combination calculations
  • Not validating that r doesn't exceed n before calculating

Edge Cases to Watch For

  • C(n,r) always equals C(n, n−r) - choosing which r items to include is equivalent to choosing which (n−r) items to exclude.
  • When r equals 0 or r equals n, the result is always 1 - there's exactly one way to choose nothing, and exactly one way to choose everything.
  • Combination counts are always less than or equal to the corresponding permutation count for the same n and r, since ordering information is discarded.
  • This formula assumes no repetition allowed and treats all n items as distinct - combinations with repetition use a different formula.

Common Use Cases

  • Calculating unordered group selections for probability problems
  • Lottery and card game odds calculations
  • Team or committee selection counting problems
  • Combinatorics and discrete math coursework
Written & fact-checked by the Calculateus TeamLast updated August 5, 2026How we verify our formulas

Frequently asked questions

When would I use combinations instead of permutations?

Use combinations whenever the order of selection doesn't matter - like choosing a 5-person committee from 20 people, or picking lottery numbers where the drawn order doesn't change your win.

Conclusion

Combinations answer 'how many different groups' while permutations answer 'how many different orderings' - getting that distinction right is the key to solving most combinatorics problems correctly. Our Probability Calculator can then use these counts to find the actual probability of a specific outcome.